document.write( "Question 1026086: There are estimates of the margin of error for confidence levels other than 95%. For a 90% confidence level and a sample size of n, the margin of error is approximately
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\n" ); document.write( "\n" ); document.write( "Suppose we wish to have a margin of error of 2% with a 90% confidence level. Approximately how many people should we interview?
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Algebra.Com's Answer #641338 by stanbon(75887)\"\" \"About 
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Suppose we wish to have a margin of error of 2% with a 90% confidence level. Approximately how many people should we interview?
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\n" ); document.write( "n = [1.645/0.02]^2*(1/2)^2 = 1691 when rounded up
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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