document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1026033>Question 1026033</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive odd integers such that their product is 47 more than 4 times their sum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641307 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> integers are x and x+2<BR>\n" );
document.write( "x(x+2)=4(2x+2)+47<BR>\n" );
document.write( "x^2+2x=8x+8+47<BR>\n" );
document.write( "x^2+2x=8x+55<BR>\n" );
document.write( "x^2-6x-55=0<BR>\n" );
document.write( "(x-11)(x+5)=0<BR>\n" );
document.write( "x=11,-5<BR>\n" );
document.write( "11 and 13 has a sum of 24 and a product of 143.  That is 4*24+47<BR>\n" );
document.write( "-5 and -3 has a sum of -8 and a product of 15.  That is 4*(-8)+47<BR>\n" );
document.write( "The pairs are 11,13 and -5,-3. </SPAN>\n" );
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