document.write( "Question 1026024: What is the domain and range of
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document.write( "y=x+1\r
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document.write( "y+x^2+1\r
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document.write( "y=√x+1 \n" );
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Algebra.Com's Answer #641305 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! y=x+1; domain and range are both (-oo,+oo) \n" ); document.write( "y=x^2+1; domain is infinite (-oo,+oo); range is [1,oo), because x^2 is never less than 0. \n" ); document.write( " \n" ); document.write( "y=sqrt(x)+1. If that is how it should be written, the domain of x is [0,oo); the range is [1,oo) \n" ); document.write( "if sqrt(x+1), then domain is [-1,oo), range [0,oo) \n" ); document.write( " |