document.write( "Question 1025988: Vanessa bought a car for $20,000 . It is expected to depreciate at a continuous rate. What will be the value of the car in 2 years? Use K - .105. The answer should be $16,212.00 I think but I need to see the how or steps. Thanks.
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Algebra.Com's Answer #641291 by MathTherapy(10553)\"\" \"About 
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Vanessa bought a car for $20,000 . It is expected to depreciate at a continuous rate. What will be the value of the car in 2 years? Use K - .105. The answer should be $16,212.00 I think but I need to see the how or steps. Thanks.
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Use the continuous compounding formula: \"A+=+Pe%5E%28rt%29\", where:
\n" ); document.write( "A = Value in t years
\n" ); document.write( "P = Original value
\n" ); document.write( "e = 2.71828.......
\n" ); document.write( "r = rate of depreciation, which in this case, is: K = - .105
\n" ); document.write( "t = time in years\r
\n" ); document.write( "\n" ); document.write( "Therefore, \"A+=+Pe%5E%28rt%29\" becomes: \"A%282%29+=+20000e%5E%28-+.105+%2A+2%29\"
\n" ); document.write( "\"A%282%29+=+20000e%5E-+.21\"
\n" ); document.write( "Depreciated value in 2 years, or \n" ); document.write( "
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