document.write( "Question 1026011: One cage contains 3 white mice and 2 black ones, and another cage contains 5 white mice and 2 black ones. A cage is chosen at random and three mice are selected. Find the expected number of white mice in the sample. \n" ); document.write( "
Algebra.Com's Answer #641271 by robertb(5830)\"\" \"About 
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Assume that each cage is equally likely to be chosen.
\n" ); document.write( "Let X = the number of white mice in the three mice chosen
\n" ); document.write( "Apparently, x = 0, 1, 2, 3.
\n" ); document.write( "Given the first cage is chosen, the following are the conditional probabilities for each value of X.
\n" ); document.write( "X -----> 0 1 2 3
\n" ); document.write( "p(x|1st cage)---> 0 3/10 6/10 1/10\r
\n" ); document.write( "\n" ); document.write( "Given the second cage is chosen, the following are the conditional probabilities for each value of X.
\n" ); document.write( "X -----> 0 1 2 3
\n" ); document.write( "p(x|2nd cage)---> 0 1/7 4/7 2/7\r
\n" ); document.write( "\n" ); document.write( "This means the combined (joint) probability mass function is as follows:\r
\n" ); document.write( "\n" ); document.write( "X -----> 0 1 2 3
\n" ); document.write( "p(x)---> 0 62/280 164/280 54/280\r
\n" ); document.write( "\n" ); document.write( "==> E(X) = \"0%2A0+%2B+1%2A%2862%2F280%29+%2B+2%2A%28164%2F280%29+%2B+3%2A%2854%2F280%29+=+1.97143\"\r
\n" ); document.write( "\n" ); document.write( "Thus, the expected number of white mice in the selection is practically 2.
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