\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Since a+b appears twice, let c = a+b \r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Get a least common denominator of ac\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Factor out
\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "So we try to factorize the trinomial like this,\r\n" );
document.write( "breaking up
as the product of
and
:\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "It doesn't take too much thinking to know that we\r\n" );
document.write( "must fill in the blank spaces with c and a to\r\n" );
document.write( "cause the product to be ac\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "And if we find the outer and inner products, we\r\n" );
document.write( "find that we get -aČ-bČ which is -(aČ+bČ).\r\n" );
document.write( "\r\n" );
document.write( "So that is the correct factorization. All that's\r\n" );
document.write( "left is to substitute (a+b) for c and simplify:\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Removing the inner parentheses we have:\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" );
document.write( " \n" );
document.write( "