document.write( "Question 1025964: How many consecutive integers beginning with 5 must be taken for the sum to equal 95.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #641223 by FrankM(1040)\"\" \"About 
You can put this solution on YOUR website!
The series has N terms. The first term is 5, the last term is 5+(N-1) which simplifies to N+4\r
\n" ); document.write( "\n" ); document.write( "The sum of a series of consecutive integers is N/2 (first term +last term) so we have \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(N)(5+(N+4))/2=95\r
\n" ); document.write( "\n" ); document.write( "(N)(N+9)=190\r
\n" ); document.write( "\n" ); document.write( "N^2+9N-190=0\r
\n" ); document.write( "\n" ); document.write( "(N-10)(N+19)=0\r
\n" ); document.write( "\n" ); document.write( "N=10\r
\n" ); document.write( "\n" ); document.write( "10 terms 5 thru 14 add to 95
\n" ); document.write( "
\n" );