document.write( "Question 1025963: a woman is 5 years younger than her husband and 3 times as old as her daughter .if the daughter attain 21 years of age after 6 years what is the present age of husband \n" ); document.write( "
Algebra.Com's Answer #641222 by mananth(16946)![]() ![]() You can put this solution on YOUR website! a woman is 5 years younger than her husband and 3 times as old as her daughter .if the daughter attain 21 years of age after 6 years what is the present age of husband\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let woman,s age be 3x now\r \n" ); document.write( "\n" ); document.write( "husband,s age is 3x+5\r \n" ); document.write( "\n" ); document.write( "daughter's age = x\r \n" ); document.write( "\n" ); document.write( "after 6 years daughter is 21 \n" ); document.write( "x+6=21 \n" ); document.write( "x=21-6=15\r \n" ); document.write( "\n" ); document.write( "mothers age = 3 *15=45\r \n" ); document.write( "\n" ); document.write( "husband's age = 45+5 = 50 years now \n" ); document.write( " |