document.write( "Question 1025963: a woman is 5 years younger than her husband and 3 times as old as her daughter .if the daughter attain 21 years of age after 6 years what is the present age of husband \n" ); document.write( "
Algebra.Com's Answer #641222 by mananth(16946)\"\" \"About 
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a woman is 5 years younger than her husband and 3 times as old as her daughter .if the daughter attain 21 years of age after 6 years what is the present age of husband\r
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\n" ); document.write( "\n" ); document.write( "let woman,s age be 3x now\r
\n" ); document.write( "\n" ); document.write( "husband,s age is 3x+5\r
\n" ); document.write( "\n" ); document.write( "daughter's age = x\r
\n" ); document.write( "\n" ); document.write( "after 6 years daughter is 21
\n" ); document.write( "x+6=21
\n" ); document.write( "x=21-6=15\r
\n" ); document.write( "\n" ); document.write( "mothers age = 3 *15=45\r
\n" ); document.write( "\n" ); document.write( "husband's age = 45+5 = 50 years now
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