document.write( "Question 1025960: One number is 3 larger than twice a second number. Find the two numbers so that their product is a maximum. \n" ); document.write( "
Algebra.Com's Answer #641220 by josgarithmetic(39617)\"\" \"About 
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\"system%28x=3%2By%2Cp=xy%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"p=%283%28y%2B3%29%29y\"\r
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\n" ); document.write( "\n" ); document.write( "\"p=%283y%2B9%29y\"\r
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\n" ); document.write( "\n" ); document.write( "\"p=3y%5E2%2B9y\"\r
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\n" ); document.write( "\n" ); document.write( "---Differentiate p.....
\n" ); document.write( "\"dp%2Fdy=2%2A3y%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "\"dp%2Fdy=6y%2B9\"\r
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\n" ); document.write( "\n" ); document.write( "\"6y%2B9=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2y%2B3=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2y=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28y=-3%2F2%29\" corresponding to \"x=3%2B%28-3%2F2%29=6%2F2-3%2F2=highlight%283%2F2=x%29\".
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