document.write( "Question 12572: How would you graph 2x+y=6
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #6412 by AdolphousC(70)\"\" \"About 
You can put this solution on YOUR website!
You first need to get 2X + Y = 6 into slope intercept form which is y = mx+b
\n" ); document.write( "

\n" ); document.write( "To do this you need to subtract 2X from both sides, giving you y = -2x + 6
\n" ); document.write( "

\n" ); document.write( "Now you know your y intercept = 6 and slope is -2
\n" ); document.write( "


\n" ); document.write( "Your y-intercept is a point on the y axis, in this case 6, so go up 6 and plot the point (0,6), your slope, -2 should always be thought of as a fraction
\n" ); document.write( "\"rise%2Frun\" -2 as a fraction is \"-2%2F1\" so your rise is -2 and your run is 1
\n" ); document.write( "


\n" ); document.write( "a rise of -2 means go down on the y-axis 2 units, and since you always run right, you move 1 unit along the x-axis, so you should now have a point at (1,4)
\n" ); document.write( "

\n" ); document.write( "Plot this point and connect your two points, thus creating a graph, it should look like the one below
\n" ); document.write( "

\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28300%2C200%2C-3%2C+10%2C+-3%2C+10%2C+-2x%2B6%29\" \n" ); document.write( "

\n" );