document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025819>Question 1025819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help, I am stucked at this question:\r<BR>\n" );
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document.write( "Find the interest rate needed for an investment of $3,000 to grow to an amount of $4,000 in 3 years  if interest is compounded continuously. Please round the answer to the nearest hundredth of percent.\r<BR>\n" );
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document.write( "I am using the compounded interest formula:<BR>\n" );
document.write( "A = P ( 1+&#12310;r/m)&#12311;^mt<BR>\n" );
document.write( "where A = $4000 and P = $3000 and t = 3 (years) and m = 1 (annually) and r = interest (percentage)<BR>\n" );
document.write( "I am stuck at this step: $4000 = $3000 &#12310;(1+r)&#12311;^3<BR>\n" );
document.write( "Suppose if this is correct up to this point, can anyone be kind enough to show me the workings in solving this? Much thanks.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #641163 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=641163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help, I am stucked at this question:\r<BR>\n" );
document.write( "\n" );
document.write( "Find the interest rate needed for an investment of $3,000 to grow to an amount of $4,000 in 3 years  if interest is compounded continuously. Please round the answer to the nearest hundredth of percent.\r<BR>\n" );
document.write( "\n" );
document.write( "I am using the compounded interest formula:<BR>\n" );
document.write( "A = P ( 1+&#12310;r/m)&#12311;^mt<BR>\n" );
document.write( "where A = $4000 and P = $3000 and t = 3 (years) and m = 1 (annually) and r = interest (percentage)<BR>\n" );
document.write( "I am stuck at this step: $4000 = $3000 &#12310;(1+r)&#12311;^3<BR>\n" );
document.write( "Suppose if this is correct up to this point, can anyone be kind enough to show me the workings in solving this? Much thanks.<BR>\n" );
document.write( "<PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">You used the formula for interest when doing REGULAR (monthly, quarterly, annually, etc.) compounding but this requires<BR>\n" );
document.write( "the formula for CONTINUOUS ompounding, which is: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28A+=+Pe%5E%28rt%29%29 ALIGN=MIDDLE  ALT=\"highlight_green%28A+=+Pe%5E%28rt%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "You solve this for r, the interest rate </SPAN>\n" );
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