document.write( "Question 1025839: A committee of4 boys and 3 girls is to be formed from a club of 10 boys and 8 girls . In how many ways can this be done. If a particular boy must be on it ? \n" ); document.write( "
Algebra.Com's Answer #641143 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A committee of 4 boys and 3 girls is to be formed from a club of 10 boys and 8 girls . In how many ways can this be done if a particular boy must be on it ? \n" ); document.write( "----- \n" ); document.write( "# of ways to pick the particular boy:: 1 \n" ); document.write( "# of ways to pick 3 other boys:: 9C3 \n" ); document.write( "# of ways to pick 3 girls:: 8C3 \n" ); document.write( "---------------------------- \n" ); document.write( "Ans: 1*9C3*8C3 = 4704 ways \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------- \n" ); document.write( " |