document.write( "Question 1025767: Solve this equation for 0≤x≤2p, giving your answer to a multiple of p.\r
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document.write( "sin2x + sinx = 0 \n" );
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Algebra.Com's Answer #641080 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " sin(2x) + sin(x) = 0\r\n" ); document.write( "2sin(x)cos(x) + sin(x) = 0\r\n" ); document.write( " sin(x)[2cos(x)+1] = 0\r\n" ); document.write( "\r\n" ); document.write( "sin(x) = 0; 2cos(x)+1 = 0\r\n" ); document.write( "x = 0, p 2cos(x) = -1\r\n" ); document.write( " cos(x) = -1/2\r\n" ); document.write( " x = 2p/3, 4p/3\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |