document.write( "Question 88271: Find the x-intercepts.
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Algebra.Com's Answer #64102 by jim_thompson5910(35256)\"\" \"About 
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\"y+=+x%5E2+%2B+4x+\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2+%2B+4x+\" Let y=0\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general form of the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B4%2Ax%2B0=0\" (notice \"a=1\", \"b=4\", and \"c=0\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+%284%29%5E2-4%2A1%2A0+%29%29%2F%282%2A1%29\" Plug in a=1, b=4, and c=0\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+16-4%2A1%2A0+%29%29%2F%282%2A1%29\" Square 4 to get 16\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+16%2B0+%29%29%2F%282%2A1%29\" Multiply \"-4%2A0%2A1\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+sqrt%28+16+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+4%29%2F%282%2A1%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B-+4%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-4+%2B+4%29%2F2\" or \"x+=+%28-4+-+4%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2F2\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=0\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=0\"\r
\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-8%2F2\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=-4\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x=-4\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B4%2Ax%2B0\" we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-14%2C+10%2C+-14%2C+10%2C1%2Ax%5E2%2B4%2Ax%2B0%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the roots are \"x=0\" and \"x=-4\". This verifies our answer\r
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\n" ); document.write( "\n" ); document.write( "So the x-intercepts are (0,0) and (-4,0)
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