document.write( "Question 88267: Find the constant term that should be added to make the following expression a perfect-square trinomial.\r
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Algebra.Com's Answer #64101 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Take half of the x coefficient -2 to get -1 like this\r
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\n" ); document.write( "\n" ); document.write( "Now square -1 \r
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\n" ); document.write( "\n" ); document.write( "\"%28-1%29%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the term to add is 1\r
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\n" ); document.write( "\n" ); document.write( "Notice if we factor\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "we get \r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%28x-1%29=%28x-1%29%5E2\" \r
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\n" ); document.write( "\n" ); document.write( "and this verifies our answer
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