document.write( "Question 1025701: I am trying to answer the below question and I believe the answer is true.\r
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Algebra.Com's Answer #640987 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%28-1%29%2Asqrt%28-1%29=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Try starting from \"x%5E2=-1\". If x is positive, \"x%5E2%3E0\", which is taught and learned in introductory algebra. \"-1\" is not positive.
\n" ); document.write( "If x is negative, then \"x%5E2%3E0\", which is taught and learned in introductory algebra. \"-1\" is not positive.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28-1%29\" is an imaginary unit, and is not \"Real\".
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