document.write( "Question 1025670: pLEASE HELP ME I AM SO CONFUSED BEEN OUT OF SCHOOL FOR OVER 30YRS AND NEVER HAD PROBLEMS LIKE THIS\r
\n" ); document.write( "\n" ); document.write( "1.Maricopa's Success scholarship fund receives a gift of $ 120000. The money is invested in stocks, bonds, and CDs. CDs pay 4 % interest, bonds pay 2 % interest, and stocks pay 7.7 % interest. Maricopa Success invests $ 35000 more in bonds than in CDs. If the annual income from the investments is $ 5835 , how much was invested in each account? \r
\n" ); document.write( "\n" ); document.write( " Maricopa Success invested $ in stocks.
\n" ); document.write( " Maricopa Success invested $ in bonds.
\n" ); document.write( " Maricopa Success invested $ in CDs. \r
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\n" ); document.write( "\n" ); document.write( "2.A chemist has three different acid solutions. The first acid solution contains 25% acid, the second contains 35% and the third contains 55%. He wants to use all three solutions to obtain a mixture of 75 liters containing 45%acid, using 3 times as much of the 55% solution as the 35% solution. How many liters of each solution should be used?\r
\n" ); document.write( "\n" ); document.write( " The chemist should use \r
\n" ); document.write( "\n" ); document.write( " liters of 25% solution,
\n" ); document.write( " liters of 35% solution, and
\n" ); document.write( " liters of 55% solution.
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Algebra.Com's Answer #640984 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
The two questions are almost the same kind. I will do just your #2 mixture percents question.\r
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\n" ); document.write( "\n" ); document.write( "x,y,z for the low, medium, and high(er) concentration acids. The quantities of them IN LITERS to use.\r
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\n" ); document.write( "\n" ); document.write( "...using 3 times as much of the 55% solution as the 35% solution.
\n" ); document.write( "This means \"z%2Fy=3\", and from this, \"z=3y\".\r
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\n" ); document.write( "\n" ); document.write( "Make the material sum equation.
\n" ); document.write( "\"x%2By%2Bz=75\", which you may use later.\r
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\n" ); document.write( "\n" ); document.write( "Substituting for z, the material sum is also \"x%2By%2B3y=75\",
\n" ); document.write( "\"x%2B4y=75\".\r
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\n" ); document.write( "\n" ); document.write( "Make the percentage relationship equation for the mixture to prepare.
\n" ); document.write( "\"%2825x%2B35y%2B55z%29%2F%2875%29=45\", which you might need effort to understand.
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\n" ); document.write( "Again substitute for z in this percents equation.
\n" ); document.write( "\"%2825x%2B35y%2B55%2A3y%29%2F75=45\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2825x%2B200y%29%2F75=45\"
\n" ); document.write( "and you should reduce this, since it can be reduced.\r
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\n" ); document.write( "\n" ); document.write( "\"%285%28x%2B40y%29%29%2F75=5%2A9\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B40y%29%2F75=9\"\r
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "Summarize your equations as a system, keeping in mind, you temporarily eliminated z.
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\n" ); document.write( "\"highlight_green%28system%28x%2B4y=75%2C%28x%2B40y%29%2F75=9%29%29\"
\n" ); document.write( "This is your system to solve for x and y. This IS a linear system; just multiply the members of the percents equation by 75.\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28system%28x%2B4y=75%2Cx%2B40y=675%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "If you not remember how to use Elimination Method, then just use Substitution Method.
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\n" ); document.write( "\"x=75-4y\"
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\n" ); document.write( "\"%2875-4y%29%2B40y=675\"
\n" ); document.write( "\"75-4y%2B40y=675\"
\n" ); document.write( "\"36y=600\"
\n" ); document.write( "\"y=600%2F36\"
\n" ); document.write( "\"y=300%2F18\"
\n" ); document.write( "\"y=150%2F9\"
\n" ); document.write( "\"highlight%28y=50%2F3%29\"
\n" ); document.write( "or
\n" ); document.write( "\"highlight%28y=16%262%2F3%29\"----------the 35% acid, liters to use
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\n" ); document.write( "FIND x.
\n" ); document.write( "\"x=75-4%2A%2816%262%2F3%29\"
\n" ); document.write( "\"highlight%28x=8%261%2F3%29\"---------liters to use of the 25% acid
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