document.write( "Question 1025618: Rohan deposit 25000 into account. He deposited some amount in saving account at simple interest 6% p.a. remaining amount in fixed deposit @12% p.a. if he gets 5700 at total interest after two years then the amount he deposit in fixed deposit is? \n" ); document.write( "
Algebra.Com's Answer #640981 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Part I 6.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 12.00% per annum ------------ Amount invested = y =
\n" ); document.write( " 25000
\n" ); document.write( "Interest----- 2850
\n" ); document.write( "
\n" ); document.write( "Part I 6.00% per annum ---x
\n" ); document.write( "Part II 12.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 25000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "for one year interest is 2850
\n" ); document.write( "6.00% x + 12.00% y= 2850
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 12 y= 285000.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -150000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 6 y= 135000
\n" ); document.write( "divide by 6
\n" ); document.write( " y = 22500
\n" ); document.write( "Part I 6.00% $ 2500
\n" ); document.write( "Part II 12.00% $ 22500
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "2500 --------- 6.00% ------- 150.00
\n" ); document.write( "22500 ------------- 12.00% ------- 2700.00
\n" ); document.write( "Total -------------------- 2850.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
\n" ); document.write( " \n" ); document.write( "
\n" );