document.write( "Question 1025671: A petroleum company has two different sources of crude oil. The first source provides crude oil that is 50% hydrocarbons, and the second one provides crude oil that is 75% hydrocarbons. In order to obtain 60 gallons of crude oil that is 70% hydrocarbons, how many gallons of crude oil must be used from each of the two sources?\r
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document.write( "first source how many gallons?
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document.write( "second source how many gallons? \n" );
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Algebra.Com's Answer #640965 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A petroleum company has two different sources of crude oil. The first source provides crude oil that is 50% hydrocarbons, and the second one provides crude oil that is 75% hydrocarbons. In order to obtain 60 gallons of crude oil that is 70% hydrocarbons, how many gallons of crude oil must be used from each of the two sources? \n" ); document.write( "---- \n" ); document.write( "Quantity:: f + s = 60 gallons \n" ); document.write( "Hydro Eq:: 0.50f + 0.75s = 0.70*60 \n" ); document.write( "------ \n" ); document.write( "50f + 50s = 50*60 \n" ); document.write( "50f + 75s = 70*60 \n" ); document.write( "----------------------------- \n" ); document.write( "Subtract and solve for \"s\":: \n" ); document.write( "25s = 20*60 \n" ); document.write( "s = (4/5)60 \n" ); document.write( "s = 48 gallons (amt. of 75% needed) \n" ); document.write( "f = 12 gallons (amt. of 50% needed) \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "---------------- \n" ); document.write( " |