document.write( "Question 1025651: if the lines x-py+ap^2=0
\n" ); document.write( "Ad x-qy+aq^2 are perpendicular
\n" ); document.write( "Show that pq=-1
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Algebra.Com's Answer #640957 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The shortcut to proving it is to know what to recognize in the standard form equation for a line. The slopes of your given lines in order are \"1%2Fp\" and \"1%2Fq\". The lines to be perpendicular will require \"%281%2Fp%29%281%2Fp%29=-1\". Multiply left and right members by \"pq\".
\n" ); document.write( ".... there, you have it.\r
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\n" ); document.write( "\n" ); document.write( "--
\n" ); document.write( "So you want a little more information for this.
\n" ); document.write( "Basic fact is, if product of the slopes of two lines is negative ONE, then the two lines are perpendicular.\r
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\n" ); document.write( "\n" ); document.write( "Put each equation into slope-intercept form.
\n" ); document.write( "\"x-py%2Bap%5E2=0\"
\n" ); document.write( "\"-py=-x-ap%5E2\"
\n" ); document.write( "\"y=%281%2Fp%29x%2Bap%5E2\"
\n" ); document.write( "-
\n" ); document.write( "\"x-qy%2Baq%5E2=0\"
\n" ); document.write( "\"-qy=-x-aq%5E2\"
\n" ); document.write( "\"y=%281%2Fq%29x%2Baq%5E2\"
\n" ); document.write( "-
\n" ); document.write( "Note the slopes of the two lines are \"1%2Fp\" and \"1%2Fq\".
\n" ); document.write( "The two lines are GIVEN as perpendicular, and this means according to the basic fact about perpendicular lines in the plane, \"%281%2Fp%29%281%2Fq%29=-1\".\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2Fp%29%281%2Fq%29%2Apq=-1%2A%28pq%29\"\r
\n" ); document.write( "\n" ); document.write( "\"1=-1%2Apq\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2A%28-1%29=-1%2Apq%2A%28-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"-1=pq\"-------done.
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