document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025641>Question 1025641</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which system of inequalities are represented in this graph linked below?\r<BR>\n" );
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document.write( "http://postimg.org/image/7y1r6c1l7/ - graph\r<BR>\n" );
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document.write( "A.) x + y > 3; -x + y > ­- 4<BR>\n" );
document.write( "B.) -x + y &#8805; ­-4;  x + y &#8804; 3<BR>\n" );
document.write( "C.) -2x + y > ­-4;  2x + y < 3<BR>\n" );
document.write( "D.) -x + y > -­4;  x + y < 3\r<BR>\n" );
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document.write( "Thanks in advance, I cant find the solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640947 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640947\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> here's a picture of your graph.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2016/031801.jpg\" alt=\"$$$\" </>\r<BR>\n" );
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document.write( "the slope intercept form of a linear equation is y = mx + b.\r<BR>\n" );
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document.write( "m is the slope.<BR>\n" );
document.write( "b is the y-intercept.\r<BR>\n" );
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document.write( "the y-intercept is the value of y when the value of x is 0.\r<BR>\n" );
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document.write( "that's the point where the graph crosses the y-axis.\r<BR>\n" );
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document.write( "the standard form of a linear equation is ax + by = c\r<BR>\n" );
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document.write( "a is the coefficient of the x term.<BR>\n" );
document.write( "b is the coefficient of the y term.<BR>\n" );
document.write( "c is the constant term.\r<BR>\n" );
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document.write( "first we'll work with the slope intercept form of the equation.\r<BR>\n" );
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document.write( "then we'll convert that form to the standard form.\r<BR>\n" );
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document.write( "the slope intercept form of the equation is y = mx + b.\r<BR>\n" );
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document.write( "m is the slope and b is the y-intercept.\r<BR>\n" );
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document.write( "we'll have 2 equations.\r<BR>\n" );
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document.write( "one of them crosses the y-axis at y = 3.<BR>\n" );
document.write( "the other crosses the y-axis at y = -4.\r<BR>\n" );
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document.write( "your two equation will be:\r<BR>\n" );
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document.write( "y = mx + 3\r<BR>\n" );
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document.write( "y = mx - 4\r<BR>\n" );
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document.write( "we replaced b with the y-intercepts that we saw on the graph.\r<BR>\n" );
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document.write( "now we look at the slope.\r<BR>\n" );
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document.write( "the line that crosses the y-axis at 3 is sloping downward from left to right.\r<BR>\n" );
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document.write( "this tells us the slope will be negative.\r<BR>\n" );
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document.write( "it starts at the point (0,3) which is the y-intercept.\r<BR>\n" );
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document.write( "we look for the next intersection that is an integer.\r<BR>\n" );
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document.write( "there are 3 that we can see.\r<BR>\n" );
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document.write( "they are at (1,2), (2,1), and (3,0).\r<BR>\n" );
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document.write( "i chose the point (3,0) to calculate the slope.\r<BR>\n" );
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document.write( "the two points i chose are (0,3) and (3,0).\r<BR>\n" );
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document.write( "let (x1,y1) = (0,3) <BR>\n" );
document.write( "let (x2,y2) = (3,0)\r<BR>\n" );
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document.write( "slope = (y2-y1)/(x2-x1) = (0-3)/(3-0) = -3/3 = -1.\r<BR>\n" );
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document.write( "replace m with -1 in the equation that has 3 as the y-intercept and you get y = -x + 3.\r<BR>\n" );
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document.write( "a similar analysis in the line that intersects the y-axis at -4 uses the points (0,-4) and (3,-1) going from left to right.\r<BR>\n" );
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document.write( "let (x1,y1) = (0,-4)<BR>\n" );
document.write( "let (x2,y2) = (3,-1)\r<BR>\n" );
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document.write( "slope = (y2-y1)/(x2-x1) = (-4-(-1))/(3-0) = (-4+1)/3 = 3/3 = 1.\r<BR>\n" );
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document.write( "replace m with 1 in the equation of the line with the y-intercept of -4 to get y = x - 4.\r<BR>\n" );
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document.write( "your equations are y = -x + 3 and y = x - 4.\r<BR>\n" );
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document.write( "the graph has a shaded region and the lines are dashed.\r<BR>\n" );
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document.write( "this indicates an inequality of > or <, but not >= or <=.\r<BR>\n" );
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document.write( "if it was >= or <=, the lines would be solid.\r<BR>\n" );
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document.write( "since they are dashed, the inequality is < or >.\r<BR>\n" );
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document.write( "the shaded region is under the line of y = -x + 3, therefore the equation is y < -x + 3.\r<BR>\n" );
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document.write( "the shaded region is above the line y = x - 4, therefore the equation is y > x - 4.\r<BR>\n" );
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document.write( "to convert these equations to standard form, do the following:\r<BR>\n" );
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document.write( "start with y < -x + 3<BR>\n" );
document.write( "add x to both sides of the equation to get x + y < 3.\r<BR>\n" );
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document.write( "start with y > x - 4<BR>\n" );
document.write( "subtract x from both sides of the equation to get -x + y > -4\r<BR>\n" );
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document.write( "your equations are x + y < 3 and -x + y > -4.\r<BR>\n" );
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document.write( "that would be selection D.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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