document.write( "Question 88254: Solve. x^2 + 1 = 17 \n" ); document.write( "
Algebra.Com's Answer #64094 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2+%2B+1+=+17\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+1+-+17=0\" Subtract 17 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2++-16=0\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general form of the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"x%5E2%2B0%2Ax-16=0\" (notice \"a=1\", \"b=0\", and \"c=-16\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-0+%2B-+sqrt%28+%280%29%5E2-4%2A1%2A-16+%29%29%2F%282%2A1%29\" Plug in a=1, b=0, and c=-16\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-0+%2B-+sqrt%28+0-4%2A1%2A-16+%29%29%2F%282%2A1%29\" Square 0 to get 0\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-0+%2B-+sqrt%28+0%2B64+%29%29%2F%282%2A1%29\" Multiply \"-4%2A-16%2A1\" to get \"64\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-0+%2B-+sqrt%28+64+%29%29%2F%282%2A1%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-0+%2B-+8%29%2F%282%2A1%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-0+%2B-+8%29%2F2\" Multiply 2 and 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-0+%2B+8%29%2F2\" or \"x+=+%28-0+-+8%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "Lets look at the first part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=8%2F2\" Add the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So one answer is\r
\n" ); document.write( "\n" ); document.write( "\"x=4\"\r
\n" ); document.write( "\n" ); document.write( "Now lets look at the second part:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-8%2F2\" Subtract the terms in the numerator\r
\n" ); document.write( "\n" ); document.write( "\"x=-4\" Divide\r
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\n" ); document.write( "\n" ); document.write( "So another answer is\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=4\" or \"x=-4\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"x%5E2%2B0%2Ax-16\" we get:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-14%2C+14%2C+-14%2C+14%2C1%2Ax%5E2%2B0%2Ax%2B-16%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the roots are \"x=4\" and \"x=-4\". This verifies our answer
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