document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025522>Question 1025522</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A regular hexagon of side length 2a is placed so that the center is at the origin, and one diagonal lies on the y-axis. Find the coordinate of the vertex located in Quadrant III.\r<BR>\n" );
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document.write( "Note: if drawn properly, the regular hexagon should only have one point IN Quadrant III. Your answer must be in terms of a.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640932 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A regular hexagon of side length 2a is placed so that the center is at the origin, and one diagonal lies on the y-axis. Find the coordinate of the vertex located in Quadrant III.<BR>\n" );
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document.write( "The side length of a hexagon = radius<BR>\n" );
document.write( "The angle of that vertex = 60 + 60 + 60 + 30 = 210 degs<BR>\n" );
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document.write( "x = 2a*cos(210) = -sqrt(3)a<BR>\n" );
document.write( "y = 2a*sin(210) = -a<BR>\n" );
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document.write( "--> (-sqrt(3)a,-a) </SPAN>\n" );
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