document.write( "Question 88257: Solve by using the quadratic formula. 2x^2 + 5x = 4\r
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Algebra.Com's Answer #64089 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2x%5E2+%2B+5x+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2+%2B+5x+-+4=0+\"Subtract 4 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the quadratic formula to solve for x:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"ax%5E2%2Bbx%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general form of the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"2%2Ax%5E2%2B5%2Ax-4=0\" (notice \"a=2\", \"b=5\", and \"c=-4\")\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+%285%29%5E2-4%2A2%2A-4+%29%29%2F%282%2A2%29\" Plug in a=2, b=5, and c=-4\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25-4%2A2%2A-4+%29%29%2F%282%2A2%29\" Square 5 to get 25\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+25%2B32+%29%29%2F%282%2A2%29\" Multiply \"-4%2A-4%2A2\" to get \"32\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28+57+%29%29%2F%282%2A2%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%2857%29%29%2F%282%2A2%29\" Simplify the square root\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%2857%29%29%2F4\" Multiply 2 and 2 to get 4\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-5+%2B+sqrt%2857%29%29%2F4\" or \"x+=+%28-5+-+sqrt%2857%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Which approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"x=0.637458608817687\" or \"x=-3.13745860881769\"\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"x=0.637458608817687\" or \"x=-3.13745860881769\"\r
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\n" ); document.write( "\n" ); document.write( "Notice when we graph \"2%2Ax%5E2%2B5%2Ax-4\" we get:\r
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\n" ); document.write( "\n" ); document.write( "when we use the root finder feature on a calculator, we find that \"x=0.637458608817687\" and \"x=-3.13745860881769\".So this verifies our answer
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