document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025603>Question 1025603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay how did I find the area of an enclosed rectangle if the entire fence length is 820ft and one side 118ft? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640882 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640882\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2L + 2W\r<BR>\n" );
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document.write( "L = length<BR>\n" );
document.write( "W = width<BR>\n" );
document.write( "P = perimeter\r<BR>\n" );
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document.write( "L = 118<BR>\n" );
document.write( "P = 820\r<BR>\n" );
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document.write( "P = 2L + 2W becomes:\r<BR>\n" );
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document.write( "820 = 2*118 + 2W\r<BR>\n" );
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document.write( "solve for W to get W = (820 - 236) / 2 = 292\r<BR>\n" );
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document.write( "L = 118<BR>\n" );
document.write( "W = 292\r<BR>\n" );
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document.write( "A = area\r<BR>\n" );
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document.write( "A = L * W = 118 * 292 = 34456 square feet.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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