document.write( "Question 1025543: Jolene invests her savings in two bank accounts, one paying 3% and the other paying 9% simple interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual interest is 2925 dollars. How much did she invest at each rate? \r
\n" ); document.write( "\n" ); document.write( "Amount invested at 3% interest is
\n" ); document.write( "Amount invested at 9% interest is
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Algebra.Com's Answer #640880 by mananth(16946)\"\" \"About 
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Jolene invests her savings in two bank accounts,\r
\n" ); document.write( "\n" ); document.write( "one paying 9% simple interest . Amount = x
\n" ); document.write( " one paying 3% and per year. Amount = 2x She puts twice as much in the lower-yielding account
\n" ); document.write( " Her annual interest is 2925 dollars. \r
\n" ); document.write( "\n" ); document.write( "2x*3%+x*9% = 2925\r
\n" ); document.write( "\n" ); document.write( "multiply by 100\r
\n" ); document.write( "\n" ); document.write( "2x+x = 292500
\n" ); document.write( "3x=292500
\n" ); document.write( "x=97500\r
\n" ); document.write( "\n" ); document.write( "Amount invested at 3% interest is 195000
\n" ); document.write( "Amount invested at 9% interest is = 97500
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