document.write( "Question 1025580: the length of a rectangle is represented by x+7 and the width is represented by x+1. If the area of the rectangle is 65 square feet, find the perimeter of this rectangle. \n" ); document.write( "
Algebra.Com's Answer #640860 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Length = (x+7) \n" ); document.write( "width = (x+1)\r \n" ); document.write( "\n" ); document.write( "Area = L * W\r \n" ); document.write( "\n" ); document.write( "(x+7)(x+1) =65\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y=1x2+8x−58 discriminant=b2−4(a)(c)=82−4(1)(−58)=296 ( 2 real solutions ) \r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "−b± sqrt(b2−4(a)(c))/√2(a)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "−8±82−4(1)(−58)/2(1)\r \n" ); document.write( "\n" ); document.write( "−8±296/2\r \n" ); document.write( "\n" ); document.write( "=−8±4×74 /2\r \n" ); document.write( "\n" ); document.write( "=−8±274 /2\r \n" ); document.write( "\n" ); document.write( "=−4±174\r \n" ); document.write( "\n" ); document.write( "=−4±174 \r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=4.602325267042627 x=−12.602325267042626 \r \n" ); document.write( "\n" ); document.write( "ignore negative\r \n" ); document.write( "\n" ); document.write( "x=4.6\r \n" ); document.write( "\n" ); document.write( "length = 11.6 & width = 5.6 \n" ); document.write( " |