document.write( "Question 1025582: In isosceles triangle AB$ (with AB = AC), point D lies on AB such that CD = CB. If angle ADC = 115 degrees, what is angle ACD (in degrees)?
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Algebra.Com's Answer #640854 by ikleyn(52781)\"\" \"About 
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document.write( "1.  angle(CDB) = 180° - angle(ADC) = 180° - 115° = 65° (as a complementary angle).\r\n" );
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document.write( "2.  angle(CBD) = angle(CDB) = 65° as the triangle CBD is isosceles.\r\n" );
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document.write( "3.  angle(ACB) = angle(ABC) = 65° as the triangle ABC is isoceles.\r\n" );
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document.write( "4.  From the triangle ABC, angle(A) = 180° - (65°+65°) = 50°.\r\n" );
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document.write( "5.  From the triangle ADC, angle(ACD) = 180° - (115°+50°) = 15°.\r\n" );
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document.write( "The problem is solved.\r\n" );
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