document.write( "Question 1025582: In isosceles triangle AB$ (with AB = AC), point D lies on AB such that CD = CB. If angle ADC = 115 degrees, what is angle ACD (in degrees)?
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Algebra.Com's Answer #640854 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "In isosceles triangle AB$ (with AB = AC), point D lies on AB such that CD = CB. If angle ADC = 115 degrees, what is angle ACD (in degrees)? \n" ); document.write( " image: http://classroom.artofproblemsolving.com/Classes/IntroGeom/Images/480402815.gif \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "1. angle(CDB) = 180° - angle(ADC) = 180° - 115° = 65° (as a complementary angle).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "2. angle(CBD) = angle(CDB) = 65° as the triangle CBD is isosceles.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "3. angle(ACB) = angle(ABC) = 65° as the triangle ABC is isoceles.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "4. From the triangle ABC, angle(A) = 180° - (65°+65°) = 50°.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "5. From the triangle ADC, angle(ACD) = 180° - (115°+50°) = 15°.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The problem is solved.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |