document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025510>Question 1025510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $20 a pound that she wishes to mix with 50 pounds of coffee worth $50 a pound to get a mixture that can be sold for $40 a pound. How many pounds of the $20 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640805 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of pounds of $20 stuff, x.  The setup looks like this:<BR>\n" );
document.write( "20x + 50(50) = 40(50 + x)<BR>\n" );
document.write( "Now solve for x.<BR>\n" );
document.write( "20x + 2500 = 2000 + 40x<BR>\n" );
document.write( "500 = 20x<BR>\n" );
document.write( "x = 25 pounds of $20 coffee </SPAN>\n" );
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