document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025511>Question 1025511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A contractor mixes concrete from bags of pre-mix for small jobs. How many bags with 3% cement should he mix with 10 bags of 18.2% cement to produce a mix containing 11% cement? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640803 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the number of bags of 3% cement, x.  Then the setup looks like this:<BR>\n" );
document.write( ".03x + .182(10) = .11(10+x)<BR>\n" );
document.write( "Now solve for x.<BR>\n" );
document.write( ".03x + 1.82 = 1.1 + .11x<BR>\n" );
document.write( ".72 = .08x<BR>\n" );
document.write( "x = 9 bags of 3% cement </SPAN>\n" );
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