document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024951>Question 1024951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The graph of (x-3)^2 + (y-5)^2=16 is reflected over the line y=2. The new graph is the graph of the equation x^2 + Bx + y^2 + Dy + F = 0 for some constants B, D, and F. Find B+D+F. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640780 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640780\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The graph of<BR>\n" );
document.write( "(x-3)^2 + (y-5)^2 = 16<BR>\n" );
document.write( "is a circle centered at (3,5) with radius of 4.<BR>\n" );
document.write( "When you reflect over the line y = 2, it is still a circle of radius 4 but its new center is at (3,-1), and its new equation is<BR>\n" );
document.write( "(x-3)^2 + (y+1)^2 = 16<BR>\n" );
document.write( "Now multiply everything out and get<BR>\n" );
document.write( "x^2 - 6x + 9 + y^2 + 2y + 1 = 16<BR>\n" );
document.write( "x^2 - 6x + y^2 + 2y - 6 = 0<BR>\n" );
document.write( "B+D+F = -10 </SPAN>\n" );
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