document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025476>Question 1025476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how muny pounds of dried fruiy costing 1.50$ per pound should be mixed with 12 pounds of granola that costs 2.00 per pound in order to make a mixture that costs 1.80$ per pound </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640759 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Same problem, different numbers.<BR>\n" );
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document.write( "How many liters of a 65% acid solution must be mixed with 10% acid solution to get 320 liters of a 30% acid solution?<BR>\n" );
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document.write( " s = amount of 65%<BR>\n" );
document.write( " t = amount of 10%<BR>\n" );
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document.write( " s + t = 320 (total solution)<BR>\n" );
document.write( " 65s + 10t = 320*30 (total acid)<BR>\n" );
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document.write( " s + t = 320 --> t = 320 - s<BR>\n" );
document.write( " 65s + 10t = 320*30 = 9600<BR>\n" );
document.write( " Sub for t<BR>\n" );
document.write( " 65s + 10(320-s) = 9600<BR>\n" );
document.write( " 75s + 3200 = 9600<BR>\n" );
document.write( " s = 6400/75<BR>\n" );
document.write( " s = 256/3 liters<BR>\n" );
document.write( " t = 704/3 liters <BR>\n" );
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