document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025478>Question 1025478</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi I need some help please the problem states to solve 4 log( 2x + 1 ) = 12. I think I understand how it simplifies to 8 log (x) + 4 log (-12) = 0 , but I'm not sure if that is the correct answer or not. Thank you for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640758 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640758\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8 log (x) + 4 log (-12) = 0<BR>\n" );
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document.write( "log(-12) is not allowed, no negative argument.\r<BR>\n" );
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document.write( "4 log( 2x + 1 ) = 12<BR>\n" );
document.write( "Divide by 4<BR>\n" );
document.write( "log(2x+1) = 3<BR>\n" );
document.write( "log(2x+1) = log(10^3) = log(1000)<BR>\n" );
document.write( "2x+1 = 1000<BR>\n" );
document.write( "2x = 999<BR>\n" );
document.write( "x = 999/2<BR>\n" );
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