document.write( "Question 1025472: How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution? \n" ); document.write( "
Algebra.Com's Answer #640755 by Alan3354(69443)\"\" \"About 
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How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution?
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\n" ); document.write( "Do it like this:
\n" ); document.write( "How many liters of a 65% acid solution must be mixed with 10% acid solution to get 320 liters of a 30% acid solution?
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\n" ); document.write( "s = amount of 65%
\n" ); document.write( "t = amount of 10%
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\n" ); document.write( "s + t = 320 (total solution)
\n" ); document.write( "65s + 10t = 320*30 (total acid)
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\n" ); document.write( "s + t = 320 --> t = 320 - s
\n" ); document.write( "65s + 10t = 320*30 = 9600
\n" ); document.write( "Sub for t
\n" ); document.write( "65s + 10(320-s) = 9600
\n" ); document.write( "75s + 3200 = 9600
\n" ); document.write( "s = 6400/75
\n" ); document.write( "s = 256/3 liters
\n" ); document.write( "t = 704/3 liters\r
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