document.write( "Question 1025472: How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution? \n" ); document.write( "
Algebra.Com's Answer #640755 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution? \n" ); document.write( "------------ \n" ); document.write( "Do it like this: \n" ); document.write( "How many liters of a 65% acid solution must be mixed with 10% acid solution to get 320 liters of a 30% acid solution? \n" ); document.write( "--------------- \n" ); document.write( "s = amount of 65% \n" ); document.write( "t = amount of 10% \n" ); document.write( "--- \n" ); document.write( "s + t = 320 (total solution) \n" ); document.write( "65s + 10t = 320*30 (total acid) \n" ); document.write( "========== \n" ); document.write( "s + t = 320 --> t = 320 - s \n" ); document.write( "65s + 10t = 320*30 = 9600 \n" ); document.write( "Sub for t \n" ); document.write( "65s + 10(320-s) = 9600 \n" ); document.write( "75s + 3200 = 9600 \n" ); document.write( "s = 6400/75 \n" ); document.write( "s = 256/3 liters \n" ); document.write( "t = 704/3 liters\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |