document.write( "Question 88242: The length of a rectangle is three times the width. If the length is increased by 4 feet and the width is decreased by 1 foot, the area will be increased by 24 square feet. What are the dimensions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #64074 by stanbon(75887)\"\" \"About 
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The length of a rectangle is three times the width. If the length is increased by 4 feet and the width is decreased by 1 foot, the area will be increased by 24 square feet. What are the dimensions of the original rectangle?
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\n" ); document.write( "Original Rectangle:
\n" ); document.write( "Let width by \"x\"; length = 3x
\n" ); document.write( "Area = x*3x = 3x^2
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\n" ); document.write( "Rectangle after change:
\n" ); document.write( "Width = x-1 ; length = 3x+4
\n" ); document.write( "Area = (x-1)(3x+4) = 3x^2+x-4
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\n" ); document.write( "EQUATION:
\n" ); document.write( "original area + 24 = changed area
\n" ); document.write( "3x^2+24 = 3x^2+x-4
\n" ); document.write( "24 = x-4
\n" ); document.write( "x = 28 feet (original width)
\n" ); document.write( "3x = 84 feet (original length)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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