document.write( "Question 88065: I always have problems with this type of word problem How can I solve this and write the equation for it? please help\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field. \n" ); document.write( "
Algebra.Com's Answer #64070 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
he length of a rectangular playing field is 5 ft less than twice its width. If the perimeter of the playing field is 230 ft, find the length and width of the field.
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\n" ); document.write( "Let x = width
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\n" ); document.write( "It says
\n" ); document.write( " \"the length of a rectangular playing field is 5 ft less than twice its width.\"
\n" ); document.write( "Therefore:
\n" ); document.write( "length = (2x - 5)
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\n" ); document.write( "If the perimeter of the playing field is 230 ft,
\n" ); document.write( "Perimeter: 2L + 2W = 230
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\n" ); document.write( "Substitute (2x-5) for L and x for w and you have:
\n" ); document.write( "2(2x-5) + 2x = 230
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\n" ); document.write( "WE can simplify, divide each term by 2 and you have
\n" ); document.write( "2x - 5 + x = 115
\n" ); document.write( "2x + x = 115 + 5; add 5 to both sides:
\n" ); document.write( "3x = 120
\n" ); document.write( "x = 120/3
\n" ); document.write( "x = 40 ft is the width:
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\n" ); document.write( "Find the length; L = 2W-5
\n" ); document.write( "2(40) - 5 = 75 ft is the length
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\n" ); document.write( "Check solution; find the perimeter with these values:
\n" ); document.write( "2(75) + 2(40) = 230; confirms our solution
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\n" ); document.write( "Make sense to you??\r
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