document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12578>Question 12578</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measures of two complementary angles are 12q-9 and 8q+14. Find the measures of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6407 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> complementary angles add up to 90.\r<BR>\n" );
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document.write( "so 12q-9 + 8q+14 = 90<BR>\n" );
document.write( "20q + 5 = 90<BR>\n" );
document.write( "20q = 85<BR>\n" );
document.write( "--> q = 85/20<BR>\n" );
document.write( "--> q = 4.25\r<BR>\n" );
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document.write( "so the 2 angles are:\r<BR>\n" );
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document.write( "12(4.25) - 9 --> 42<BR>\n" );
document.write( "8(4.25) + 14 --> 48\r<BR>\n" );
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document.write( "jon<BR>\n" );
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