document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025439>Question 1025439</A>: <I><SPAN STYLE=\"word-break: break-all;\"> All Seasons Plumbing has two service trucks that frequently need repair. If the probability the first truck is available is 0.76, the probability the second truck is available is 0.46, and the probability that both trucks are available is 0.41:\r<BR>\n" );
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document.write( "What is the probability neither truck is available? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640693 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p(a) = .76<BR>\n" );
document.write( "p(b) = .46<BR>\n" );
document.write( "p(a and b) = .41\r<BR>\n" );
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document.write( "p(a or b) = p(a) + p(b) - p(a and b)\r<BR>\n" );
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document.write( "that becomes .76 + .46 - .41 which is equal to .81\r<BR>\n" );
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document.write( "p(not(a or b)) is equal to 1 - p(a or b) which is equal to 1 - .81 = .19\r<BR>\n" );
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document.write( "the probability that neither is available is equal to 1 minus the probability that either is available.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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