document.write( "Question 88165: Would someone show me step by step how to figure out this word problem? Thank you
\n" ); document.write( "The length of a rectangle is 1cm more than 5 times its width. If the area of the rectangle is 79 cm^2, find the dimensions of the rectangle to the nearest thousandth.
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Algebra.Com's Answer #64067 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is 1cm more than 5 times its width. If the area of the rectangle is 79 cm^2, find the dimensions of the rectangle to the nearest thousandth.
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\n" ); document.write( "Let x = width of the rectangle
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\n" ); document.write( "It says \"the length of a rectangle is 1cm more than 5 times its width\" Therefore:
\n" ); document.write( " (5x + 1) = the length
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\n" ); document.write( "If the area of the rectangle is 79 cm^2,
\n" ); document.write( "L * W = 79
\n" ); document.write( "Which is:
\n" ); document.write( "x(5x+1) = 79; substituted x for width and (x+1) for length
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\n" ); document.write( "5x^2 + x = 79; multiplied what was inside the brackets
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\n" ); document.write( "5x^2 + x - 79; subtracted 79 from both sides, gives us a quadratic equation
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\n" ); document.write( "This equation has to be solved by the quadratic formula a^2 + bx + c = y
\n" ); document.write( "in our equation: a = 5; b = 1; c =-79
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1%5E2+-+4%2A5%2A-79+%29%29%2F%282%2A5%29+\"
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\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1+-+%281580%29+%29%29%2F%2810%29+\"
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\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1++%2B+1580+%29%29%2F%2810%29+\"; minus a minus is a plus
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\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+1581+%29%29%2F%2810%29+\"
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\n" ); document.write( "WE are only interested in the positive solution here:
\n" ); document.write( "\"x+=+%28%28-1+%2B+39.762%29%29%2F%2810%29+\"; found the square root of 1581
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\n" ); document.write( "\"x+=+%2838.762%29%2F%2810%29+\"
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\n" ); document.write( "x = 3.876 is the width, Then the length = (5*3.876) + 1 = 20.38
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\n" ); document.write( "Check solutions:
\n" ); document.write( "3.876 * 20.38 = 78.99 ~ 79
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\n" ); document.write( "Was this enough steps to put on the right track here?\r
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