document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025382>Question 1025382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A logging barge on the Mississippi River travels 24 miles upstream in 3 hours. The return trip takes the barge only 2 hours. Find the rate of the barge in still water.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640664 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640664\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let speed of barge in still water be x mph<BR>\n" );
document.write( "and current speed = y mph\r<BR>\n" );
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document.write( "upstream distance = 24<BR>\n" );
document.write( "time = 3 hours\r<BR>\n" );
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document.write( "upstream speed = 24/3 = 8 mph\r<BR>\n" );
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document.write( "downstream distance = 24 miles<BR>\n" );
document.write( "time = 2 hours<BR>\n" );
document.write( "speed = 24/2=12 mph\r<BR>\n" );
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document.write( "x+y =12<BR>\n" );
document.write( "x-y =8\r<BR>\n" );
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document.write( "add the equations\r<BR>\n" );
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document.write( "2x = 20<BR>\n" );
document.write( "x= 10 \r<BR>\n" );
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document.write( "speed of bargein still water  = 10 mph </SPAN>\n" );
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