document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025267>Question 1025267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The  length of a rectangle exceeds its width by 6 units. If each dimension were increased by 3 units,the area would be increased by 57 square units. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640598 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640598\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of a rectangle is A = length times width...A=LW...<BR>\n" );
document.write( "Here L = W + 6...substituting we get<BR>\n" );
document.write( "A=(W+6)W <BR>\n" );
document.write( "Now, with the increase<BR>\n" );
document.write( "(W+9)(W+3)=(W+6)W + 57<BR>\n" );
document.write( "Solve this...<BR>\n" );
document.write( "W^2 + 12W + 27 = W^2 + 6W + 57<BR>\n" );
document.write( "6W = 30<BR>\n" );
document.write( "W = 5 and then<BR>\n" );
document.write( "L = 11 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );