document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=88213>Question 88213</A>: <I><SPAN STYLE=\"word-break: break-all;\"> does any one have time to help me with a problem? factor each expression 5x2+13x+6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #64051 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=64051\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is what I call Advanced Trinomial Factoring again.\r<BR>\n" );
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document.write( "5x2+13x+6\r<BR>\n" );
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document.write( "First times First MUST be:<BR>\n" );
document.write( "(5x____)(x____)\r<BR>\n" );
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document.write( "The Last times Last has several possibilities.  It could be 1*6 or 6*1.  It could be 2*3 or 3*2.  You need to get a combination of numbers such that the OUTER times OUTER plus the INNER times INNER will add up to the middle term which is 13x.  The combination that works is 3*2.  See below:<BR>\n" );
document.write( "(5x+3)(x+2)\r<BR>\n" );
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document.write( "Notice that the OUTER times OUTER would be 5x*2 = 10x, and the INNER times INNER would be 3*x = 3x.  This adds up to 13x, so this is the answer:\r<BR>\n" );
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document.write( "(5x+3)(x+2) \r<BR>\n" );
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document.write( "R^2  </SPAN>\n" );
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