document.write( "Question 1025112: Please help me this problem is driving me crazy.\r
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document.write( "Write the sum using sigma notation: \r
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document.write( "1/1⋅2+1/2⋅3+1/3⋅4+⋯+1/219⋅220=
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document.write( "A
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document.write( "∑ B
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document.write( "n=1
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document.write( ", where \r
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document.write( "A=
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document.write( "B=
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Algebra.Com's Answer #640448 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Note that each term is of the form 1/(n*(n+1)) where n ranges from 1 to 219 (*not* 220).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In fact, the sum is equal to 1 - (1/220) = 219/220. But that is a completely different problem. \n" ); document.write( " |