document.write( "Question 1025061: Car X and car Y traveled the same 80km route. If car X took 2 hours and car Y traveled at an average speed that was 50% faster than the average speed of car X, how long did it take car Y to travel the route? \n" ); document.write( "

Algebra.Com's Answer #640418 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = time in hrs for car Y
\n" ); document.write( "Let $\"+s+\"$ = speed in km/hr for car X
\n" ); document.write( "----------
\n" ); document.write( "Equation for car X:
\n" ); document.write( "(1) $\"+80+=+s%2A2+\"$
\n" ); document.write( "Equation for car Y:
\n" ); document.write( "(2) $\"+80+=+1.5s%2At+\"$
\n" ); document.write( "------------------
\n" ); document.write( "(1) $\"+s+=+80%2F2+\"$
\n" ); document.write( "(1) $\"+s+=+40+\"$ km/hr
\n" ); document.write( "Plug this result into (2)
\n" ); document.write( "(2) $\"+80+=+1.5s%2At+\"$
\n" ); document.write( "(2) $\"+80+=+1.5%2A40%2At+\"$
\n" ); document.write( "(2) $\"+80+=+60t+\"$
\n" ); document.write( "(2) $\"+t+=+4%2F3+\"$
\n" ); document.write( "(2) $\"+t+=+1+%2B+1%2F3+\"$ hrs
\n" ); document.write( " $\"+%281%2F3%29%2A60+=+20+\"$
\n" ); document.write( "Car Y's time is 1 hr and 20 min
\n" ); document.write( "---------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+80+=+1.5s%2At+\"$
\n" ); document.write( "(2) $\"+80+=+1.5s%2A%284%2F3%29+\"$
\n" ); document.write( "(2) $\"+3%2A80+=+1.5%2A4%2As+\"$
\n" ); document.write( "(2) $\"+240+=+6s+\"$
\n" ); document.write( "(2) $\"+s+=+40+\"$ km/hr
\n" ); document.write( "OK \n" ); document.write( "

\n" );