document.write( "Question 1025105: Please help me solve this word problem, using substitution or elimination:\r
\n" ); document.write( "\n" ); document.write( "How much of a perfume that sells for $35 dollar per ounce should be mixed with a perfume that sells for $15 dollar per ounce to make a 3-ounce bottle of perfume that can be sold for $63?
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Algebra.Com's Answer #640412 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+a+\" = ounces of $35/oz perfume needed
\n" ); document.write( "Let \"+b+\" = ounces of $15/oz perfume needed
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\n" ); document.write( "\"+63%2F3+=+21+\"
\n" ); document.write( "Perfume selling for $21/oz is desired
\n" ); document.write( "(1) \"+a+%2B+b+=+3+\"
\n" ); document.write( "(2) \"+%28+35a+%2B+15b+%29+%2F+3+=+21+\"
\n" ); document.write( "---------------------------
\n" ); document.write( "(2) \"+35a+%2B+15b+=+63+\"
\n" ); document.write( "Multiply both sides of (1) by \"+15+\" and
\n" ); document.write( "subtract (1) from (2)
\n" ); document.write( "(2) \"+35a+%2B+15b+=+63+\"
\n" ); document.write( "(1) \"+-15a+-+15b+=+-45+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "\"+20a+=+18+\"
\n" ); document.write( "\"+a+=+.9+\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"+.9+%2B+b+=+3+\"
\n" ); document.write( "(1) \"+b+=+2.1+\"
\n" ); document.write( "-----------------
\n" ); document.write( "0.9 ounces of $35/oz perfume is needed
\n" ); document.write( "2.1 ounces of $15/oz perfume is needed
\n" ); document.write( "----------------------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+35a+%2B+15b+%29+%2F+3+=+21+\"
\n" ); document.write( "(2) \"+%28+35%2A.9+%2B+15%2A2.1+%29+%2F+3+=+21+\"
\n" ); document.write( "(2) \"+%28+31.5+%2B+31.5+%29+%2F+3+=+21+\"
\n" ); document.write( "(2) \"+63%2F3+=+21+\"
\n" ); document.write( "(2) \"+63+=+63+\"
\n" ); document.write( "OK
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