document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1025047>Question 1025047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A shop has 48 notebooks for sale. The number of blue notebook is 12 less than twice the number of red notebooks. How many blue notebooks are there?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640342 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b+r = 48 (1)<BR>\n" );
document.write( "b = 2r-12 Use this value for b in equation (1):<BR>\n" );
document.write( "2r-12+r = 48 add 12 on both sides and add r on left:<BR>\n" );
document.write( "3r = 60 <BR>\n" );
document.write( "r = 20 There are 20 red notebooks and the problem says:<BR>\n" );
document.write( "b = 2r-12 = 2(20)-12=40-12= 28 There are 28 blue notebooks </SPAN>\n" );
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