document.write( "Question 1025025: Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.
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Algebra.Com's Answer #640334 by Alan3354(69443)\"\" \"About 
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Find the area of the region enclosed by the graph of the equation x^2 + y^2 = 4x + 6y+13.
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\n" ); document.write( "x^2 + y^2 = 4x + 6y+13.
\n" ); document.write( "x^2-4x + y^2-6y = 13.
\n" ); document.write( "Complete the square for x & y.
\n" ); document.write( "x^2-4x+4 + y^2-6y+9 = 13+4+9 = 26
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\n" ); document.write( "r^2 = 26
\n" ); document.write( "\"Area+=+pi%2Ar%5E2+=+26pi\"
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