document.write( "Question 1024963: One printing press can produce a newspaper in six hours running alone. . A second press can produce the paper and nine hours running alone a third press can produce the paper in nine hours running alone. A third press could produce the paper in 12 hours working alone. A late breaking headline cause the newspaper to change the paper later than usual. If all three presses are running , How long will it take to produce the newspaper \n" ); document.write( "

Algebra.Com's Answer #640312 by josmiceli(19441) $\"\"$ $\"About$

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Add the different rates of printing
\n" ); document.write( "to get their rate printing together.
\n" ); document.write( "Let $\"+t+\"$ = time in hours to
\n" ); document.write( "produce paper
\n" ); document.write( " $\"+1%2F6+%2B+1%2F9+%2B+1%2F12+=+1%2Ft+\"$
\n" ); document.write( "Multiply both sides by $\"+36t+\"$
\n" ); document.write( " $\"+6t+%2B+4t+%2B+3t+=+36+\"$
\n" ); document.write( " $\"+13t+=+36+\"$
\n" ); document.write( " $\"+t+=+2+%2B+10%2F36+\"$
\n" ); document.write( "Convert the fraction to minutes
\n" ); document.write( " $\"+%28+10%2F36+%29%2A60+=+600%2F36+\"$
\n" ); document.write( " $\"+600%2F36+=+16+%2B+2%2F3+\"$ min
\n" ); document.write( "Convert the fraction to seconds
\n" ); document.write( " $\"+%28+2%2F3+%29%2A60+=+40+\"$ sec
\n" ); document.write( "--------------------------
\n" ); document.write( "Working together, the presses take
\n" ); document.write( "2 hrs 16 min 40 sec
\n" ); document.write( "--------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+1%2F6+%2B+1%2F9+%2B+1%2F12+=+1%2F2.7692+\"$
\n" ); document.write( " $\"+.1667+%2B+.1111+%2B+.0833+=+.3611+\"$
\n" ); document.write( " $\"+.3611+=+.3611+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );