document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1024897>Question 1024897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> prove the following<BR>\n" );
document.write( "1.tanAsinA+cosA=secA<BR>\n" );
document.write( "2.sinA-sinAcos^2A=sin3A<BR>\n" );
document.write( "3.sinAcscA-cos^A=sin^2A<BR>\n" );
document.write( "4.sinA+sinAcot^2A=cscA<BR>\n" );
document.write( "5.tanA+cotA=secAcscA<BR>\n" );
document.write( "6.1/1-sinA+1/1+sinA=2sec^2A </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #640293 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=640293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> prove the following<BR>\n" );
document.write( "1.tanAsinA+cosA=secA<BR>\n" );
document.write( "---<BR>\n" );
document.write( "sin^2/cos + cos = sec<BR>\n" );
document.write( "Multiply thru by cos<BR>\n" );
document.write( "sin^2 + cos^2 = 1 QED<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "2.sinA-sinAcos^2A=sin3A<BR>\n" );
document.write( "It it's sin^3 on the right, divide thru by sine.<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "3.sinAcscA-cos^A=sin^2A<BR>\n" );
document.write( "1 - cos^2 = sin^2 QED<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "4.sinA+sinAcot^2A=cscA<BR>\n" );
document.write( "sin + cos^2/sin = csc<BR>\n" );
document.write( "Multiply thru by sine<BR>\n" );
document.write( "sin^2 + cos^2 = 1 QED<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "5.tanA+cotA=secAcscA<BR>\n" );
document.write( "sin/cos + cos/sin = 1/(sin*cos)<BR>\n" );
document.write( "Multiply thru by sin*cos<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "6.1/1-sinA+1/1+sinA=2sec^2A<BR>\n" );
document.write( "((1+sin) + (1-sin))/(1-sin^2) = 2sec^2<BR>\n" );
document.write( "2/cos^2 = 2/cos^2 QED<BR>\n" );
document.write( "================================<BR>\n" );
document.write( "I'm still looking for an example where working 1 side only makes a difference.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );