document.write( "Question 88187: Find the magnitude of the following vector: v=4i-2j \n" ); document.write( "
Algebra.Com's Answer #64029 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
To calculate the norm of the vector use the following formula:\r
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\n" ); document.write( "\n" ); document.write( " where is the dot product of the given vector with itself\r
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\n" ); document.write( "\n" ); document.write( "Remember the dot product of the vector with itself is:\r
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\n" ); document.write( "\n" ); document.write( " Calculate the dot product of the radicand\r
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\n" ); document.write( "\n" ); document.write( " Multiply\r
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\n" ); document.write( "\n" ); document.write( " Add\r
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\n" ); document.write( "\n" ); document.write( " Simplify if possible\r
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\n" ); document.write( "\n" ); document.write( "So \r
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\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "Lets use Pythagorean's Theorem to check our work\r
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\n" ); document.write( "\n" ); document.write( "Notice if we draw the vector we get\r
\n" ); document.write( "\n" ); document.write( " Plot of the vector (black line) with the vector components (green)\r
\n" ); document.write( "\n" ); document.write( "We can see that the vector has x and y components, which form the legs of the triangle. We can also see that the legs are 4 units and 2 units\r
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\n" ); document.write( "\n" ); document.write( "Since we have a triangle with legs of 4 , 2 and a hypotenuse of x(our unknown side), we can use Pythagoreans theorem to find the unknown side.\r
\n" ); document.write( "\n" ); document.write( "Pythagoreans theorem
\n" ); document.write( "\"a%5E2%2Bb%5E2=c%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"4%5E2%2B2%5E2=c%5E2\" Plug in a=4 and b=2 and lets solve for c\r
\n" ); document.write( "\n" ); document.write( "\"1+6+%2B+4+=++c++%5E+2\" Square each individual term\r
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\n" ); document.write( "\n" ); document.write( "\"2+0+=++c++%5E+2\" Combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"s+q+r+t+%28+2+0+%29+=+s+q+r+t+%28++c++%5E+2+%29\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%285%29=c\" simplify\r
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\n" ); document.write( "\n" ); document.write( "So the length of the hypotenuse is \"2%2Asqrt%285%29\". This verifies our answer
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